12x^2-19x-10=

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Solution for 12x^2-19x-10= equation:


Simplifying
12x2 + -19x + -10 = 0

Reorder the terms:
-10 + -19x + 12x2 = 0

Solving
-10 + -19x + 12x2 = 0

Solving for variable 'x'.

Factor a trinomial.
(-5 + -12x)(2 + -1x) = 0

Subproblem 1

Set the factor '(-5 + -12x)' equal to zero and attempt to solve: Simplifying -5 + -12x = 0 Solving -5 + -12x = 0 Move all terms containing x to the left, all other terms to the right. Add '5' to each side of the equation. -5 + 5 + -12x = 0 + 5 Combine like terms: -5 + 5 = 0 0 + -12x = 0 + 5 -12x = 0 + 5 Combine like terms: 0 + 5 = 5 -12x = 5 Divide each side by '-12'. x = -0.4166666667 Simplifying x = -0.4166666667

Subproblem 2

Set the factor '(2 + -1x)' equal to zero and attempt to solve: Simplifying 2 + -1x = 0 Solving 2 + -1x = 0 Move all terms containing x to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + -1x = 0 + -2 Combine like terms: 2 + -2 = 0 0 + -1x = 0 + -2 -1x = 0 + -2 Combine like terms: 0 + -2 = -2 -1x = -2 Divide each side by '-1'. x = 2 Simplifying x = 2

Solution

x = {-0.4166666667, 2}

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